At a certain temperature, 0.4011 mol of N2 and 1.561 mol of H2 are placed in a 4.50 L container. N2(g)+3H2(g)↽−−⇀2NH3(g)

At equilibrium, 0.1601 mol of N2 is present. Calculate the equilibrium constant, c .

It is a product

27. =3,500,000 x 4,000 = 14,000,000,000

Answer is: the equilibrium  shifts toward the reactants, to the left side of chemical reaction.it is because lead(ii) nitrate dissociates in water: pb(no₃)₂ → pb²⁺(aq) + 2no₃⁻(aq).according to lechatelier's principle, the position of equilibrium moves to counteract thechange (more lead cations, common ion), the position of equilibrium will move so that the concentration ofproducts decrease and concentration of reactants of chemical reaction increase.read more on -