The Mole 7
Acellus
Now that you know the scaling factor, simply
multiply each subscript of the empirical formula
by this number and you will have your molecular
formula.
on Resources
What is the molecular formula for a compound,
having an empirical formula of CH20, and a
molar mass of 150 g/mol?
CL?Huu
Enter the subscript that goes in the green box.
Enter

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2