A chemist needs to find out how large of a container would be required to contain the products of an ammonia decomposition. If 8. 91 mol H2 are produced during the reaction, how many moles of N2 are produced? 2. 97 mol N2 26. 7 mol N2 8. 91 mol N2.

you gotta add the following molecules so we can give u an answer

explanation:

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole