(3) Unlike spectrophotometry (think of the single beam Spec20 used in Exp. 5), Raman spectroscopy uses a narrowly focused laser for incoming radiation. Would you expect a change in your experimental data, particularly your calibration curve, if you used a standard 1.00 cm cuvette instead of small glass vials

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

no but i do not usually comment or use my voice that much when it comes to social media

its first and third is your answer i did the qustion the fourth isnt right

air

in a tire you fill a tire with air

then a couple days later you check the air pressure in the tire

hope this mark me brainliest