1. In a titration, a 25cm3 sample of nitric acid, HNO3, was used to react with 100cm3 of 0.50 mol/dm3 sodium hydroxide (NaOH) solution. A) Calculate the number of moles of sodium hydroxide used.

B) Calculate how many moles of nitric acid react.

C) Calculate the concentration of nitric acid in mol/dm3.

Explanation:

1. In a titration, a 25cm3 sample of nitric acid, HNO3, was used to react with 100cm3 of 0.50 mol/dm3 sodium hydroxide (NaOH) solution.

A) Calculate the number of moles of sodium hydroxide used.

the NaOH has 0.5 moles each liter, so 10 ml has 0.05 moles

B) Calculate how many moles of nitric acid react.

1 mole of HNO3 REACTS WITH ONE MOLE OF NAOH

SINCE NAOH WAS 0.05 MOLES, HNO3 WAS 0.05 MOLES

C) Calculate the concentration of nitric acid in mol/dm3.

THESE MOLES OF HNO3 WERE IN 25/1000 L OR 25x10^-3L

SO THE CONCENTRATION OF HNO3 IS

0.05 MOLES/ (25X10^-3) = 2MOLES/LITER

CHECK

2 MOLES/LITER HAS 0.2 MOLES IN 100 ML AND 0.2/4=0.05 MOLES IN 25 ML

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.