How many grams of BaCI2 will be required to prepare 185ml of 0.675m solution?

So, molarity is defined as the number of moles of solute per liter of solution. In your case, a 0.77 M solution will contain 0.77 moles of sodium chloride, your solute, in 1.0 L of solution.

Your target solution has a volume of

985mL⋅1 L103mL=0.985 L

which means that it will contain

0.985L solution⋅= 0.77 M0.77 moles NaCl1L solution=0.75845 moles NaCl

Sodium chloride has a molar mass of 58.44 g mol−1, which basically means that one mole of sodium chloride has a mass of 58.44 g.

In your case, 0.75845 moles of sodium chloride will have a mass of

0.75845moles NaCl⋅58.44 g1mole NaCl=∣∣ ∣∣¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯aa44 gaa∣∣−−−−−−−−

The answer is rounded to two sig figs, the number of sig figs you have for the molarity of the solution.

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