Bone was dissolved in HCl to give a solution of CaCl2. An excess of potassium oxalate was added to 50.00 mL of this solution to precipitate all of the calcium as CaC2O4(calcium oxalate). What was the molarity of CaCl2 in the original solution, if 0.9460 g of calcium oxalate was collected after precipitation?

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

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