A helium-filled balloon at 1.00 atm pressure has a volume of 1.280 L. It is placed in a freezer and its volume decreases, stopping at 1.000 L. (Assume that the static internal and external pressures are equal, that the balloon contains only helium, and helium behaves as an ideal gas.)
- Calculate ΔE for the gas in the balloon.

the answer is the first option

explanation:

just googled it m8. not that hard

lol

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied

hypostyle hall;