How many milliliters of a stock solution of 6.60 M HNO3 would you have to use to prepare 0.100 L of 0.530 M HNO3?

it's c. elements are placed in rows based on how may valencies electrons have.

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer