Answers: 3
Chemistry, 22.06.2019 14:30
Consider the reduction reactions and their equilibrium constants. cu+(aq)+eββ½βββcu(s)pb2+(aq)+2eββ½βββpb(s)fe3+(aq)+3eββ½βββfe(=6.2Γ108=4.0Γ10β5=9.3Γ10β3 cu + ( aq ) + e β β½ β β β cu ( s ) k =6.2Γ 10 8 pb 2 + ( aq ) +2 e β β½ β β β pb ( s ) k =4.0Γ 10 β 5 fe 3 + ( aq ) +3 e β β½ β β β fe ( s ) k =9.3Γ 10 β 3 arrange these ions from strongest to weakest oxidizing agent.
Answers: 3
Chemistry, 22.06.2019 20:20
Nitric acid can be formed in two steps from the atmospheric gases nitrogen and oxygen, plus hydrogen prepared by reforming natural gas. in the first step, nitrogen and hydrogen react to form ammonia: (g) (g) (g) in the second step, ammonia and oxygen react to form nitric acid and water: (g) (g) (g) (g) calculate the net change in enthalpy for the formation of one mole of nitric acid from nitrogen, hydrogen and oxygen from these reactions. round your answer to the nearest .
Answers: 3
Chemistry, 22.06.2019 20:30
We are hoping to create 5.72 grams of glucose. the plant was given 4.75 liters of co2 and 2.81 g of h20. which reactant was the limiting reagent? how much excess mass did we have of the other reactant?
Answers: 3
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