6. Neon has 10 electrons - 2 in the inner shell and 8 in the outer shell. This arrangement of 8 electrons in the outer shell is extremely stable and makes neon inert, with a valence of zero. Sodium has 11 electrons - 2
in the first shell, 8 in the next shell, and I in the outer shell. Fluorine has 9 electrons - 2 in the first shell
and 7 in the outer shell. How could sodium and fluorine from a compound in which both elements would
be like neon with 8 electrons in the outer shell?

Let look at EC of Sodium(Na)

Now look at EC of Fluorine

Now the Compound will be

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

i think its 100.

hope this !