Balance the following equation: __C3H8 __O2 __CO2 __H2O propane + oxygen  carbon dioxide + water
and answer questions #15 & #16 based on the balanced equation.
15. How many dm3 of oxygen at STP would be required to react completely with 38.8g of propane? (3 marks)
** 1dm3 = 1000mL
16. How many grams of water can be generated from the combustion of 40.0g of propane in an excess of oxygen? (3 marks)

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole