A student is interested in how the number of fish treats affects the speed of fish. She has 4 fishbowls. She places 3 fish in each bowl. She places each fishbowl under the same amount of light. She keeps the water temperature at 75°F for all four bowls. She places ¼ teaspoon of regular fish food in each bowl. Finally, She places 2 fish treats in the first bowl, 4 fish treats in the second bowl, 6 fish treats in the third bowl, and no fish treats in the fourth bowl. Then, she then observes and measures the speed of the fish.1) What is the independent variable?2) What is the dependent variable?3) What is the control?4) What is a constant?

Density and pressure

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.

Answerchemical energy;