Can someone check if my answer is correct??? I will award crown, points, and thanks could someone check if my answer is correct???

Equation
H2SO4(aq)+2NaOH(s)—> Na2SO4(aq)+ 2H2O(l)

2.20/39.9970= 0.05500413 which is the limiting reagent

0.05500413 mol NaOH= (2 mol H2O)/(2 mol NaOH)= 0.05500413 mol H2O

Convert moles of H2O to mass
0.05500413x18.02= 0.99117434

% yield of H2O = 0.743/ 0.99117434= 75.0%