What is the mass in grams of NaCN in 120.0mL of a 2.40x10-5 M
solution?

ANSWER: 1.41 x grams

EXPLANATION:

1. The formula for mass is m=nM therefore we need to find moles (n) because we don't have that yet.

n = ( × ) x 0.12     (I converted 120.0 mL to L, which makes it 0.12)

n = 0.00000288 mol

2. Now we can find the mass.

m = n x M

m = 0.00000288 x 49.0072   (molar mass, M, of NaCN is 49.0072)

m = 0.00014114073 grams ≈ 1.41 x grams

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .

5 structural isomers

the isomers are:

n-exane :   ch3ch2ch2ch2ch2ch3

2-methylpentane :   ch3ch(ch3)ch2ch2ch3

3-methylpentane :   ch3ch2ch(ch3)ch2ch3

2,3-dimethylbutane :   (ch3)2chch(ch3)2

2,2-dimethylbutane :   (ch3)3cch2ch3