How many grams of O are in 765 g of N, O?​

408g

Explanation:

Relative atomic mass of NO: 14+16 =30

16/30*100= 53.3%(percentage by mass of O in NO)

53.3/100*765= mass of O

=408g

278grams, assuming N,O is actually N2O.

Explanation: Is "N,O" really supposed to read NO or N2O? This assumes N2O, laughing gas. I see another post used NO, so the problem is covered either way.

The molar mass of N2O is 44 g/mole. 765g would be 17.38 moles of N2O. That means we also have 17.38 moles of O. The molar mass of O (not O2) is 16 g.mole.

(17.38 moles(*(16 g/mole) = 278 grams of O

Another approach is to calculate the percentage of O in N2O:

N: 2*14 = 28

O: 1*16 = 16

N2O: = 44

% O is 16/44 = 36.3%

0.363*765 = 278 grams (same answer)

that's what i got you can count the number of atoms

water at room temperature is flowing through a pipe with pressure taps located 10 ft apart along one section of the pipe, which are connected to a mercury (s=13.6) manometer.