Scenario 3 Kanye has been noticing that his backup dancers seem very sluggish. He wants to set up an experiment
to see how he could help them get their freshness back. He has a total of 24 backup dancers on his tour,
so he divides them into three groups of eight. He decides to make no changes to Group A, and allow
them to continue their regular routine of dancing all night, and going out after the show with irregular
sleeping patterns. Group B, however, is asked not to go out after the show and return to their busses to
relax, getting at least eight hours of sleep a night. Group C is also asked not to go out after the show
and get at least eight hours of sleep, but are also asked to exercise at least 30 minutes when they wake
up. After a week of their new schedules, Kanye decides to watch recording of the next three shows in
his bus. He notices Group A is as sluggish as ever. Group B and Group Clook very fresh though and
complete the show with as much energy as they started.
Indentify the following and explain your decision,
1. What was Kanye's initial observation?
2. Indentify the Control Group
3. Indentify the Independent Variable
4. Indentify the Dependent Variable
5. What should Kanye's conclusion be?
6. What error do you see in Kanye's experiment.

Ok where is the image ?

  remember that hf is only the energy of one photon. not two. not three. one.  1) 5.12 * 10^3 photons  find the energy of one photon, then determine how many photons are needed to reach the sensitivity.  e = hf  = (6.626 * 10^-34 js)(5.95 * 10^19 hz)  = 3.94247 * 10^-14 j per photon  (2.02 * 10^-10 j) / (3.94247 * 10^-14 j/photon) = 5123.69149 photons  round to three sig figs.  2) 5.77 * 10^-17 j  energy of pulse = energy per photon * number of photons  = hfn  = (6.626 * 10^-34 js)(1.66 * 10^13 hz)(5250)  = 5.774559 * 10^-17 j  round to three sig figs.  3) 4.07 * 10^8 kj/mol  10^12 pm = 1 m  c = fλ  f = c/λ  e = hf  = hc/λ  = [(6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.94 * 10^-12 m)](1 kj/1000 j)(6.02 * 10^23 photons/mol)  = 40702571.4 kj/mol  round to three sig figs.  4) 9.94 * 10^-1 m  e = hc/λ  λ = hc / e  = (6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.00 * 10^-25 j)  = 0.9939 m  round to three sig figs.  5) 9.06 * 10^3 photons  energy of pulse = energy per photon * number of photons  number of photons = energy of pulse / energy per photon  = energy of pulse / (hf)  = (3.87 * 10^-13 j) / [(6.626 * 10^-34 js)(6.45 * 10^16 hz)]  = 9055.23695 photons  round to three sig figs.  6) 2.78 * 10^-15 j  this is problem 1, except in reverse.  sensitivity = minumum number of photons * energy per photon  = (5930)(6.626 * 10^-34 js)(7.077 * 10^14 hz)  = 2.78070758 × 10^-15 j  round to three sig figs.