PLEASE HELP ASAP PLEASE PUT THE ANSWER ON HERE NOT IN ANOTHER FILE THANKS The electron in a hydrogen atom can undergo a transition from n = 6 to n = 1, emitting a photon with energy 2.11 × 10–18 J. (2 points)

i. What is the frequency of this transition?

ii. How does this transition show that the energy of a photon is quantized?

C. Why is it impossible for an electron to have the quantum numbers n = 3, l = 0, ml = 1, ms = + ?

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .

0.88m hope i am correct : )

the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.