Bam makes a second solution, adding 5.01 g of Co(CH3COO)2 to 39.93 mL of H2O. Calculate the concentration of this solution in mole fraction. MWCo(CH3COO)2= 177.0212 g/mol

MWH2O= 18.015 g/mol

Density of water= 0.9975 g/mL

Consider the reaction: 2al(s) + fe2o3(s) → al2o3(s) + 2fe(s) the δhf for fe2o3(s) = -824.3 kj/mole. the δhf for al2o3(s) = -1675.7 kj/mole. finish the equation. δhrxn = [(1)( kj/mole) + (2)( kj/mole)] - [(1)( kj/mole) + (2) ( kj/mole)]