42. How would you prepare 1.00 L of a 0.50-M solution of each of the following? A. H2SO4 from “concentrated" (18 M) sulfuric acid B. HCl from “concentrated” (12 M) reagent
C. NiCl2 from the salt NiCl2 6H2O
D. HNO3 from “concentrated” (16 M) reagent
E. Sodium carbonate from the pure solid​

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Explanation:

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since electrons are negative the answer is neagtaive

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.