In questions 1 to 4, take the molar volume to be 24 dm3 (24 000 cm3) at rtp. 1 Calculate the amount in moles of each of the following:
a )2.4 dm3 of Oz at rtp
b )480 dm3 of He at rtp
c )100 cm3 of CO2 at rtp
d )1500 cm3 of N2 at rtp

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole