Electrolysis of aqueous copper(2) sulfate half ionic equation

Copper is less reactive than hydrogen, so copper (Cu) is produced at the negative electrode. The half equation is: Cu2+ + 2e- → Cu

The hydroxide ion is more reactive than the sulphate ion, therefore this forms water (H2O) and oxygen at the positive electrode.

fe 55.85 g/mol and h2o 18.02 g/mol.