How many moles of Al are in 2.16 mol of Al2O3 ?​

n(Al2O3) = 2.16 mol. n(Al) = ? = 4.32 moles.

n(Al2O3) = 2.16 mol. n(Al)

= n (Al) =2 × n(Al203)

= 2 × 2.16

= 4.32 mols

i just calculated it all out, and not including weekends, and all the different days off. as of this school year (2018-2019) students are spending 2198 hours in school this year