Explain the reaction that would occur in a galvanic cell between solutions of Al 3+and Pb 2+ . Identify the oxidation and reduction reactions and the location of each reaction. Then, use the standard reduction potential tables to determine the cell potential.

Al ==> Al^3+ + 3e

Pb^2+ + 2e ==> Pb

Oxidation is the loss of electrons. Reduction is the gain of electrons. Which half rxn above lost and which gained?

For the potential of the cell, look up the reductions potentials, change the sign of the Al half cell, add in the potential for the Pb and add them.

Explanation:

the answer is:  

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