A mixture of gases flows through a pipe at 5 m/sec at 10,000 kPa (10 Mpa), 308o K. The volumetric analysis of the gas is 40% carbon dioxide (CO2 ), 60% methane (CH4 ). For a pipe inside diameter of 2.0 cm, find the volumetric and mass flow rates of the gas mixture for a) an ideal gas mixture, b) using Amagats law and compressibility factors for the various gases.

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percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally