Determine whether each of these reactions occur through an SN1 , SN2 , E1, or E2 mechanism. A. 1 bromo pentane is treated with sodium methanethiolate in acetonitile to give a thioether product. A. The mechanism of reaction A is: E2 SN2 E1 SN1 B. 1 bromo pentane is treated with sodium methoxide in methanol to give an ether product. B. The mechanism of reaction B is: E1 SN1 E2 SN2 C. 1 bromo pentane is treated with potassium tert butoxide in tert butanol to give 1 pentene. C. The mechanism of reaction C is: E1 SN2 E2 SN1

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

the correct answer is:

a. formation of precipitation

a electronegativity decreases beacuse the size of nucleus is bigger.