Hurry PLEASEEE How many grams are 1.20 x 10^°25molecules of
calcium iodide?
Please show work!:)

19.9 mol

Explanation:

Use Avogadro’s number to convert formula units of CaI₂ to moles of CaI₂.

1 mol CaI₂ ≡ 6.022 × 10²³ formula units CaI₂

Moles of CaI₂ = 1.20 × 10²⁵ × (1 /6.022 × 10²³)

Moles of CaI₂ = 19.9 mol

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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