Question 10 of 30 What is the change in the freezing point of water when 35.0 g of sucrose is
dissolved in 300.0 g of water?
Ktof water = -1.86°C/mol
molar mass sucrose = 342.30 g/mol
i value of sugar = 1
A. 0.0606 °C
B. 0.217°C
C. -0.183°C
D. -0.634°C
SUBMIT

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.