How many joules are required to convert 16.5 g g of ice at 0.0 ∘C ∘ C to liquid water at 32.0 ∘C ∘ C ? The heat of fusion of water is 334 J J /g g .

5511 J

Explanation:

Applying,

Q = Cm Equation 1

Where Q = amount of heat required to convert ice, C = Heat of fusion of water, m = mass of ice

From the question,

Given: C = 334 J/g, m = 16.5 g

Substitute these values into equation 2

Q = 334(16.5)

Q = 5511 J

Hence, the amount of heat required is 5511 J

the formula for the conversion of temperature from degree celsius to kelvin is:

the sample of water at is converted to kelvin temperature by using the above formula as:

on comparing the two samples of water at or we can say that at and at respectively. the difference between the temperatures of two samples of water is:

hence, one can say that the sample of water at is greater than the sample of water at by .