Draw structures for the reactant and product on scratch paper. Then choose all sequences of reagents that will achieve the depicted transformation. There is more than one correct answer. Wrong answers count against you. 2-butanol → 1-butanol
1. HBO 1. HCI 1. TsCV/pyridine 1. t-BuOK 1. NaOEt 01. (H2SO4)
2. NaOEt 2, t-BuOK .2. t-BuOK 2. BH3 2, H20 2. H2SO4, 2, H20 2. NaOH
3. BH3-THF 3. H2O2. NaOH , A 3. Hg(OAc) H20 4. NaBH4 3. Hg(OAc) 3. BH3. THE
4. H2O2. NaOH 4. H2O 4. NaBH4

i need mutiple choices

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol

i just learnt this recently but i need to look through my notes again

може ли да зареждате повече информация, моля