Write down a step by step process of finding the volume of CO₂ produced during the fermentation of C₆H₁₂O₆ at STP.

Step 1: Write a balanced chemical equation of the reaction

Step 2: Convert the mass of glucose given to moles of glucose by dividing with the molar mass of glucose, 180 g/mol:

Step 3: Using the mole ratio in the equation of reaction, determine the moles of CO₂ produced:

Step 4: Convert moles of CO₂ to volume in litres of CO₂ at STP:

Explanation:

Fermentation is a complex chemical process whereby microorganisms such as yeast are used in converting carbohydrates such as glucose into ethanol and carbon dioxide under anaerobic conditions:

Step 1: Write a balanced chemical equation of the reaction

Theequation of the fermentation of glucose, C₆H₁₂O₆ at STP is as follows:

C₆H₁₂O₆ (aq) > 2 C₂H₅OH (l) + 2 CO₂ (g)

Step 2: Convert the mass of glucose given to moles of glucose by dividing with the molar mass of glucose, 180 g/mol:

Moles of glucose = mass of glucose given/molar mass of glucose = x g/ 1180 g/ mol = x moles of glucose

Step 3: Using the mole ratio in the equation of reaction, determine the moles of CO₂ produced:

From the equation of reaction, 1 mole of C₆H₁₂O₆ produces 2 moles of CO₂.

Therefore, x moles of C₆H₁₂O₆ will produce 2x moles of CO₂

Step 4: Convert moles of CO₂ to volume in litres of CO₂ at STP:

1 mole of a gas at STP has a volume of 22.4 L

1 mole of CO₂ has a volume of 22.4 L

2x moles of CO₂ has a volume of 2x × 22.4 L

since electrons are negative the answer is neagtaive