Hydrogengasand oxygengas react to form water vapor. Suppose you have of and of in a reactor. Calculate the largest amount of that could be produced. Round your answer to the nearest .

The question is incomplete. The complete question is :

Hydrogen gas and oxygen gas react to form water vapor . Suppose you have 11.0 mol of and 13.0 mol of in a reactor. Calculate the largest amount of that could be produced. Round your answer to the nearest 0.1 mol .

Solution :

The balanced reaction for reaction is :

11.0                      13.0

11/2                       13/1     (dividing by the co-efficient)

6.5 mol               13 mol    (minimum is limiting reagent as it is completely consumed during the reaction)

Therefore, is limiting reagent. It's stoichiometry decides the product formation amount from equation above it is clear that number of moles for will be produced = number of moles of

                                     = 11.0 mol

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.  

1 is the answer to this problem