The graph shows the volume of a gaseous product formed during two trials of a reaction. A different concentration of reactant was used during each trial, whereas the other factors were kept constant. A graph is shown with two graph lines sloping upwards. The title on the x axis is Time and the title on the y axis is Amount of Product. The graph line with a steeper slope is labeled Trial X and the other is labeled Trial Y.

Which of the following statements explains which trial has a lower concentration of the reactant? (5 points)
Trial X, because the final volume of product formed is lower than Trial Y.
Trial X, because this reaction was initially fast and later stopped completely.
Trial Y, because the reaction was initially slow and later stopped completely.
Trial Y, because the volume of product formed per unit time is lower than Trial X.

Trial Y, because the volume of product per unit time is lower than Trial X

Explanation:

In the chemistry experimental setup, the amount of gaseous product formed by the different concentration of the trials are measured and the result is plotted on a graph

The given graph, shows;

The vertical, y-axis = The amount of product

The horizontal, x-axis = Th time of the reaction

Trial X = The graph line with a steeper slope

Trial Y = The graph line

Increase in the concentration f the reactants, increases the number of collisions, and therefore, the number of effective collisions that gives the product also increases, and the overall rate of reaction increases

A more concentrated reactants produce more product in a shorter time (yield more product in less time) than a less concentrated one, and a more concentrated reactant would have a steeper slope and therefore produce more volume of the product in less time than a less concentrated reactant, which produces a lower volume in the same time

Therefore, the trial that has a lower concentration of the reactant is Trial Y, because the volume of product per unit time is lower than Trial X.

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the answer to your question is c.

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