The characteristics of two different types of reactions are shown below: Reaction A: Electrons are gained by the atoms of an element.
Reaction B: Protons are lost by the atom of an element.

Which statement is true about the atoms of the elements that participate in the two reactions?

Their identity changes in both Reaction A and Reaction B.
Their identity changes in Reaction A but not in Reaction B.
Their identity changes in Reaction B but not in Reaction A.
Their identity remains the same in both Reaction A and Reaction B.

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Heat is involved in chemical change in two ways; chemical changes either result in heat being added to or removed from an object, and chemical changes require a certain amount of heat before they can take place.

The correct answer is:   bri hope this answer was ! : )

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.