This question is worth three points. The following acid and base solutions are placed in a calorimeter at constant pressure: 25.0 mL of 0.10 M HCl solution and 50.0 mL of 0.20 M NaOH. The total vol-ume of the solution is 75.0 mL.

The water in the mixture has a specific heat of 4.184 J/g◦C. The solution is in-itially at 19.5◦C and at the end of the reaction is at 24.7◦C.

a. Write the balanced chemical equation for the reaction. Include states of matter and subscripts.
b. Calculate the heat q for this reaction using the calorimetry equation (mc△T). Assume the density of the solution is 1.0 g/mL (d=m/V).
c. Calculate the number of moles of HCl added to the reaction.
d. Calculate the moles of NaOH added to the reaction.
e. Determine which reactant is the limiting reactant.
f. Use the relation q +△H = 0 to find the enthalpy change for the reaction.
g. Find the molar heat of reaction by using △H/n where n is the number of moles of the limiting reactant. Recall that the limiting reactant is the reac-tant that produces the smaller amount of products in a reaction.

86400 seconds

Explanation:

Since 1 day equals 24 hours, and there are 60 minutes in 1 hour. Also, 60 seconds make a minute.

So, to find the number of seconds in a day, we need to find the number of minutes in a day since 1 day = 24 hours.

So, the number of minutes in a day = 1 day × 24 hours/day × 60 minutes/hour = 24 hours × 60 minutes/hour = 24 × 60 minutes = 1440 minutes.

So, we have that 1440 minutes = 1 day.

So, to find the number of seconds in 1 day, we find the number of seconds in 1440 minutes.

So, 1 day × 1440 minutes/day × 60 seconds/min = 1440 minutes/day × 60 seconds/minute = 1440 × 60 seconds = 86400 seconds.

So, there are 86400 seconds in 1 day.

part 1: the half-life of the element is 22 years.

part 2: it will take 132.02 year for the sample to decay from 308.0 g to 4.8125 g.

explanation:

part 1: there are two ways to determine the half life time.

first way: the half life time can be determined directly from its definition as it is the time required for the sample to decay to its half concentration.

from the data the initial concentration was 45.0 g and decayed to its half value (22.5 g) in 22.0 years.

second way: the radio active decay is considered first order reaction so we can use the laws of first order reactions.

k = (1/t) ln (a/a-x), where k is the rate constant of the reaction,

t is the time of the reaction

a is the initial concentration of the reactant

a-x is the remaining concentration at time (t)

a = 45.0 g the initial concentration at t = 0 year.

at t = 22 year, a-x = 22.5 g

then k = (1/22 year) ln (45.0 g/ 22.5 g) = 0.0315 year-1.

the half-life time (t1/2) = ln 2/ k = 0.693/ k =0.693/ 0.0315 = 22 years.

part 2:

using the same law k = (1/t) ln (a/a-x),

using the given data; a = 308.0 g and a-x = 4.8125 g and the calculated k from the part 1 (k = 0.0315 year-1)

t = (1/k) ln (a/a-x) = (1/0.0315) ln (308.0/ 4.8125) = 132.02 years

answer: any goods being imported from another country may be subject to issued by the federal government are tariffs

explanation:  

tariffs are a tax on anything that are imported from abroad. government use them to protect and boost their local industries and the thought is that they encourage consumers to buy local instead of importing and they will hope will protect jobs and economy in the country that implements them