Aluminum hydroxide is insoluble in pure water but dissolves in a solution of sodium hydroxide because: Select the correct answer below: hydroxide ions neutralize the Al3 ion, a Lewis acid aluminum participates in an acid-base reaction in the presence of sodium hydroxide the excess of hydroxide ions pushes the equilibrium toward further dissolution of Al(OH)3 aluminum forms a complex ion with excess hydroxide

aluminum forms a complex ion with excess hydroxide

Explanation:

Complex formation accounts for the dissolution of certain compounds. For instance,reaction of aluminum and sodium hydroxide yields insoluble aluminum hydroxide as follows;

Al(s) + 3NaOH(aq) > Al(OH)3(s) +Na(s)

However, in excess NaOH, the solid aluminum hydroxide dissolves as due to the formation of a complex Al(OH)4^- in the solution.

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.

a is the answer to this question

explanation: