Find the oxidation number of:
A. sulfur in S032-
B. nickel in NiO2
c. iron in Fe(OH)2

A. 4+.

B. 4+

C. 2+.

Explanation:

Hey there!

In this case, according to the given substances, it turns out possible for us to find the oxidation number of each element by applying the concept of charge balance in all of them as shown below:

A. sulfur in S032- : overall charge is 2- and the oxidation number of oxygen is 2-, thus:

B. nickel in NiO2 : overall charge is 0 and the oxidation number of oxygen is 2-, thus:

C. iron in Fe(OH)2: overall charge is 0 and the oxidation state of the OH ion is 1-, thus:

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h let me think

a 20-cm-long, cylindrical graphite (pure carbon) rod is inserted into an oxidizing atmosphere at 1145 k and 1.013 x 105 pa pressure. the oxidizing process is limited by the diffu- sion of oxygen counterflow to the carbon monoxide that is formed on the cylindrical surface.