What is the specific heat of a substance if 373 J is required to raise the temperature of a 312 g sample by 15°C?

0.080 J/g °C

General Formulas and Concepts:

Thermodynamics

Specific Heat Formula: q = mcΔT

Explanation:

Step 1: Define

[Given] q = 373 J

[Given] m = 312 g

[Given] ΔT = 15 °C

[Solve] c

Step 2: Find Specific Heat

Step 3: Check

Follow sig fig rules and round. We are given 2 sig figs as our lowest.

0.079701 J/g °C ≈ 0.080 J/g °C

Topic: AP Chemistry

Unit: Thermodynamics

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