Answer the following question: Calculate the mass of 45.0 L of F2 at 87.0° C and 750. mm Hg.

Use the Ideal Gas Law formula and here are values for R:

8.134 (L * kPa)/(mol * K)

0.0821 (atm * L)/(mol * K)

62.364 (L * mmHg)/(mol * K)

Include the following with your

Which Gas Law constant did you use or which "R" value did you use? Why?
The numerical answer to the question.
An explanation of the correct number of significant figures you will use for the numerical answer.

The mass of 45.0 L of at 87.0° C and 750 mm Hg is 56.605 g.

Explanation:

Given: Volume = 45.0 L

Temperature = = (87.0 + 273) K = 360 K

Pressure = 750 mm Hg (1 mm Hg = 0.00131579 atm) = 0.98 atm

Formula used to calculate moles is as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

Moles is the mass of a substance divided by its molar mass. So, mass of (molar mass = 37.99 g/mol) is calculated as follows.

Thus, we can conclude that the mass of 45.0 L of at 87.0° C and 750 mm Hg is 56.605 g.

well in order to answer this question you have to provide more information < 3

1. they vary with a higher number because boiling is way hotter than melting