When magnesium is heated in air, most of the magnesium reacts with the oxygen of the air, but a significant amount does react with the nitrogen of the air. If water had not been added to your initial product, a mixture of magnesium oxide and magnesium nitride would have resulted. What error in the percentage magnesium determined for your product would have resulted if a portion of the product were magnesium nitride instead of magnesium oxide? Explain.

l dont know l am s sorry

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally