Si 40 g de un compuesto C6H10O5 se disuelven en 500 g de agua, determine el punto de ebullición de esta solución. (Agua: temperatura de ebullición 100 °C y Ke = 0,52 °C/m)

The question is: If 40 g of a compound C6H10O5 are dissolved in 500 g of water, determine the boiling point of this solution. (Water: boiling temperature 100 ° C and Kb = 0.52 ° C / m).

The boiling point of given solution is .

Explanation:

Given: Mass of solute = 40 g

Mass of solvent = 500 g (1 g = 0.001 kg) = 0.5 kg

Molality is the moles of solute present in kg of solvent.

Moles is the mass of substance divided by its molar mass. Hence, moles of (molar mass = 162.141 g/mol) is calculated as follows.

Now, molality of the solution is calculated as follows.

The boiling point is calculated as follows.

where,

m = molality

Substitute the values into above formula as follows.

As the boiling point of water is 100 degree Celsius. So, the boiling point of solution is as follows.

Thus, we can conclude that the boiling point of given solution is .

the answer would be a

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.