If 6.50 L of water vapor at 50.2 °C and 0.121 atm reacts with excess iron, how many grams of iron(III) oxide will be produced? 2Fe(s)+3H2O(g)⟶Fe2O3(s)+3H2(g)

1.60 g of Fe₂O₃

Explanation:

We'll begin by calculating the number of mole water that reacted. This can be obtained as follow:

Volume (V) = 6.50 L

Temperature (T) = 50.2 °C = 50.2 + 273 = 323.2 K

Pressure (P) = 0.121 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Number of mole (n) =?

PV = nRT

0.121 × 6.5 = n × 0.0821 × 323.2

0.7865 = n × 26.53472

Divide both side by 26.53472

n = 0.7865 / 26.53472

n = 0.03 mole

Thus, 0.03 mole of water reacted.

Next, we shall determine the number of mole of Fe₂O₃ produced from the reaction. This can be obtained as follow:

2Fe + 3H₂O —> Fe₂O₃ + 3H₂

From the balanced equation above,

3 moles of H₂O reacted to produce 1 mole Fe₂O₃.

Therefore, 0.03 mole of H₂O will react to produce = (0.03 × 1)/3 = 0.01 mole of Fe₂O₃.

Thus, 0.01 mole of Fe₂O₃ was produced from the reaction.

Finally, we shall determine the mass of 0.01 mole of Fe₂O₃. This can be obtained as follow:

Mole of Fe₂O₃ = 0.01 mole

Molar mass of Fe₂O₃ = (56×2) + (16×3)

= 112 + 48

= 160 g/mol

Mass of Fe₂O₃ =?

Mass = mole × molar mass

Mass of Fe₂O₃ = 0.01 × 160

Mass of Fe₂O₃ = 1.60 g

Therefore, 1.60 g of Fe₂O₃ were produced.

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates

because of all the things that happen around the us, many people get into arguments which sadly could get physical, but we should actually make a change for that.