A chemist determines by measurements that 0.0800 moles of bromine liquid participate in a chemical reaction. Calculate the mass of bromine liquid that participates. Round your answer to 3 significant digits.

The mass of bromine liquid that participates in  a chemical reaction=12.8 g

Explanation:

We are given that

Total number of moles of bromine liquid participate in chemical reaction=0.0800 moles

We have to find the mass of bromine liquid that participates.

Atomic mass of Br=79.9 g

1  mole of bromine liquid=2 atomic mass of bromine (Br)

1 mole of bromine liquid () =

0.0800 moles of  bromine liquid= g

0.0800 moles of  bromine liquid=12.784 g

0.0800 moles of  bromine liquid g

Hence, the mass of bromine liquid that participates in  a chemical reaction=12.8 g

a) the particles of the chair are strongly held together.