How many moles of lithium nitrate are theoretically produced if we start with 3.0 moles of Ca(NO3)2 and 3.0 moles of Li3PO4? Reaction: 3Ca(NO3)2 + 2Li3PO4 → 6LiNO3 + Ca3(PO4)2

6.0 mol LiNO₃

Explanation:

First we need to determine which reactant is the limiting reactant:

We calculate with how many Ca(NO₃)₂ moles would 3.0 moles of Li₃PO₄ react, using the stoichiometric coefficients of the reaction:

There are not as many Ca(NO₃)₂ moles, so Ca(NO₃)₂ is the limiting reactant.

Using the number of moles of the limiting reactant, we calculate how many moles of LiNO₃ would be formed:

the only liquid elements at standard temperature and pressure are bromine (br) and mercury (hg). although, elements caesium (cs), rubidium (rb), francium (fr) and gallium (ga) become liquid at or just above room temperature.

explanation:

i think the answer is terrae but not 100 percent sure. ▓▬▬ §