How many moles of lithium nitrate are theoretically produced if we start with 3.0 moles of Ca(NO3)2 and 3.0 moles of Li3PO4? Reaction: 3Ca(NO3)2 + 2Li3PO4 → 6LiNO3 + Ca3(PO4)2

6.0 mol LiNO₃

Explanation:

First we need to determine which reactant is the limiting reactant:

We calculate with how many Ca(NO₃)₂ moles would 3.0 moles of Li₃PO₄ react, using the stoichiometric coefficients of the reaction:

There are not as many Ca(NO₃)₂ moles, so Ca(NO₃)₂ is the limiting reactant.

Using the number of moles of the limiting reactant, we calculate how many moles of LiNO₃ would be formed:

elements

explanation:

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