Practice by predicting what would happen if the following underwent beta decay: (2 iv. Carbon -10 +
v. Cesium-137 +
vi. Thorium-234 +

See explanation and image attached

Explanation:

During beta emission, neutrons are converted into protons and electrons. The anti neutrino balances the spins.

When a nucleus undergoes beta emission, the mass number of the daughter nucleus produced in the process is the same as that of the parent nucleus but the atomic number of the daughter nucleus increases by one unit.

The product of the beta decay of the nuclides shown in the question is described in the image attached to this answer.

i can ! i just need to know what the paragraph is! : p

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.