Iron reacts with copper (I) sulfate to produce copper and iron (II) sulfate. If 4.32x10^25 particles of copper (I) sulfate react, how many moles of copper will be produced?
Fe + Cu2504 --> FeSO4 + 2Cu

143.48 moles of copper will be produced.

Explanation:

We are given:

Number of particles of copper (I) sulfate =

According to the mole concept:

number of particles is contained in 1 mole of a compound

So, number of particles will be contained in = of copper (I) sulfate

The given chemical equation follows:

By the stoichiometry of the reaction:

If 1 mole of copper (I) sulfate produces 2 moles of Cu

So, 71.74 moles of copper (I) sulfate will produce = of Cu

Hence, 143.48 moles of copper will be produced.

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