g 250. mL of a solution is created and has a molarity of 1.50 M. What is the molality of this solution if the volume and density of the pure solvent is about the same as the volume and density of the final solution and the density of the pure solvent is 1.15 g/mL

1.30 m

Explanation:

First we calculate the number of moles of solute in the solution, using the definition of molarity:

Molarity = moles / litersConverting 250 mL ⇒ 250 / 1000 = 0.250 Lmoles = 1.50 M * 0.250 L = 0.375 moles

Then we calculate the mass of solvent, using the given volume and density:

1.15 g/mL * 250 mL = 287.5 gConverting 287.5 g to kg ⇒ 287.5 / 1000 = 0.2875 kg

Now we calculate the molality of the solution:

molality = moles of solute / kg of solvent = 0.375 mol / 0.2875 kgmolality = 1.30 m

The air is going to come out because of the low pressure.

The answer is d- principle of faunal succession.