For the unbalanced reaction below, calculate how many grams of oxygen form when 2.72 g of potassium chlorate completely reacts. KClO3(s) --> KCl(s) + O2(g)

1.06g O2

Explanation:

Let's first balance the equation.

2KClO3 > 2KCl + 3O2

We're going to go from:

Grams of KClO3: 2.72gto moles, using molar mass of KClO3: 122.5g/molWe'll convert to O2 using a mole ratio, where we have 2 mols of KClO3 to 3 mols of O2.To grams of O2 using molar mass: 32g/mol

The activity series is shown in the attached picture. if the element is below the other, then you can displace the other. following the activity series as a guide, the reactions are as follows: nickel and aluminum chloride3 ni + 2 alcl₃  → 3 nicl₂ + 2 albarium and copper bromideba + cubr  →  no reaction because cu is less oxidizable than bapotassium nitrate and aluminum3 kno₃ + al  → al(no₃)₃ + 3 ksodium phosphate and zincnaso₄ + zn  → znso₄ + na

A.(nh4)(2co3)is the correct answer