17. A sample of oxygen gas has volume 150.0 mL, at 0.947 atm, what will be the volume of the gas at 750.12 mm of Hg if temperature remain constant. ​

143.9 mL is the new volume for the gas.

Explanation:

Let's apply one of the gases law to solve this problem:

Boyle's law states that the product of pressure and volume remains constant when the T° is not modified.

P₁ . V₁ = P₂ . V₂

Be careful because we have T° in mmHg. We need to convert to atm:

750.12 mmHg . 1 atm / 760 mmHg = 0.987 atm

We replace data:

150 mL . 0.947 atm = 0.987 atm . V₂

V₂ = (150 mL . 0.947 atm) / 0.987 atm

V₂ = 143.9 mL

This term P . V comes from the Ideal Gases Law

P . V = n . R . T

it's all four options.

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.