Os produtos da combustão do H₂S e SO₂ gasoso são mostrados em reações abaixo. H₂(g) + S(s) → H₂S(g) Δ H = -21 KJ S(s) + O₂(g) → SO₂ (g) Δ H = -297 K H₂(g) + 1/2O₂(g) → H₂O(g) Δ H = -242 KJ conclui-se que a energia desprendida na combustão de 1 mol de H₂S(g) segunda a equação é: H₂(g) + 1/2O₂(g) → SO₂ (g) + H₂O(g) Δ H = ? *
1 ponto
a) - 67 Kj
b) + 34 Kj
c) - 560 Kj
d) -34 Kj
e) - 518 Kj
Answers: 1
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Os produtos da combustão do H₂S e SO₂ gasoso são mostrados em reações abaixo. H₂(g) + S(s) → H₂S(g)...
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